- ✓$\ce{K \ kg\ mol^{-1}}$ or $\ce{K(molality)^{-1}}$
- B$\ce{mol kg K^{-1}}$ or $\ce{K^{-1}(molality)}$
- C$\ce{kg mol^{-1} K^{-1}}$ or $\ce{K^{-1}(molality)^{-1}}$
- D$\ce{K mol kg^{-1}}$ or $\ce{K(molality)}$
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$(i)$ $A$ and $D$ both form blue-violet colour with ninhydrin.
$(ii)$ Lassaigne extract of $\mathrm{C}$ give positive $\mathrm{AgNO}_{3}$ test and negative $\mathrm{Fe}_{4}\left[\mathrm{Fe}(\mathrm{CN})_{6}\right]_{3}$ test.
$(iii)$ Lassaigne extract of $\mathrm{B}$ and D gives positive sodium nitroprusside test
Based on these observations which option is correct ?

$\mathrm{N}_{2}(\mathrm{g})+3 \mathrm{H}_{2}(\mathrm{g}) \rightleftharpoons 2 \mathrm{NH}_{3}(\mathrm{g})$
the correct option is
$\frac{2}{3}A{l_2}{O_3} \to \frac{4}{3}Al + {O_2},{\Delta _r}G = + 940\,kJ\,mo{l^{ - 1}}$
The potential difference needed for the electrolytic reduction of aluminium oxide ............... $\mathrm{V}$