MCQ
A chemist has $4$ samples of artificial sweetner $A$. $\mathrm{B}, \mathrm{C}$ and $\mathrm{D}$. To identify these samples, he performed certain experiments and noted the following observations :

$(i)$ $A$ and $D$ both form blue-violet colour with ninhydrin.

$(ii)$ Lassaigne extract of $\mathrm{C}$ give  positive $\mathrm{AgNO}_{3}$ test and negative $\mathrm{Fe}_{4}\left[\mathrm{Fe}(\mathrm{CN})_{6}\right]_{3}$ test.

$(iii)$ Lassaigne extract of $\mathrm{B}$ and D gives positive sodium nitroprusside test

Based on these observations which option is correct ?

  • $A $: Aspartame ; $B $: Saccharin ; $C $: Sucralose ;$ D $; Alitame
  • B
    $A$ : Alitame ; $B $: Saccharin ; $C$ : Aspartame ; $D$ ; Sucralose
  • C
    $A$ : Saccharin ; $B$ : Alitame ; $C$ : Sucralose ; $D$ ; Aspartame
  • D
    $A$ : Aspartame ; $B$ : Alitame ; $C$ : Saccharin ;$ D$ ; Sucralose

Answer

Correct option: A.
$A $: Aspartame ; $B $: Saccharin ; $C $: Sucralose ;$ D $; Alitame
a
(i) Blue voilet color with Ninhydrine $\rightarrow$ amino acid derivative. So it cannot be saccharide or sucralose.

(ii) Lassaigne extract give + ve test with $\mathrm{AgNO}_{3} .$ So $\mathrm{Cl}$ is present, -ve test with $\mathrm{Fe}_{4}\left[\mathrm{Fe}(\mathrm{CN})_{6}\right]_{3}$ means $\mathrm{N}$ is absent. So it can't be Aspartame or Saccharine or Alitame, so $\mathrm{C}$ is sucralose.

(iii) Lassaigne solution of $B$ and $D$ given $+ve$ sodium nitroprusside test, so it is having $S$, so it is Saccharine and Alitame.

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free