MCQ
The unit of equivalent conductivity is
- A$ohm \,cm$
- ✓$oh{m^{ - 1}}c{m^2}\,{(gm\,\;equivalent)^{ - 1}}$
- Cohm $c{m^2}\,(gm\,\,equivalent)$
- D$S\,c{m^{ - 2}}$
where $A _{ eq }=$ equivalent conductance
$C =$ concentration in $eq / L$
$\therefore$ Units of $A _{\text {eq }}$ are $ohm ^{-1} cm ^2\left( g - eq ^{-1}\right)$
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structure of $(A)$ is
$Pt ( s )\left| H _2( s )( latm )\right| H ^{+}\left( aq ,\left[ H ^{+}\right]=1\right)|| Fe ^{3+}( aq ), Fe ^{2+}( aq ) \mid \operatorname{Pt}( s )$
Given : $E _{ Fe ^{3+} / e ^{2 *}}^0=0.771\,V$ and $E _{ H ^{+}+\frac{1}{2} H _2}^0=0 V , T =298\,K$
If the potential of the cell is $0.712\,V$ the ratio of concentration of $Fe ^{2+}$ to $Fe ^{2+}$ is $........$.(Nearest integer)