MCQ
The unit of ionic product of water ${K_w}$ are
- A$Mo{l^{ - 1}}\,{L^{ - 1}}$
- B$Mo{l^{ - 2}}\,{L^{ - 2}}$
- C$Mo{l^{ - 2}}\,{L^{ - 1}}$
- ✓$Mo{l^2}\,{L^{ - 2}}$
$\left. H _2 O ( l )+ H _2 O ( l ) \rightleftharpoons H _3 O ^{+} \text {(aq. }\right)+ OH ^{-} \text {(aq.) or }$
$H _2 O ( l ) \rightleftharpoons H _3 O ^{+}( aq )+ OH ^{-}( aq ) .$
As per laws of mass action : $K _{ c }=\frac{\left[ H ^{+}\right]\left[ OH ^{-}\right]}{\left[ H _2 O \right]}$
$K _{ c } \times\left[ H _2 O \right]= K _{ w }=\left[ H ^{+}\right]\left[ OH ^{-}\right]$
We can see that units of $K _w$ are equal to units of $\left[ H ^{+}\right] \times\left[ OH ^{-}\right]$
Units of $\left[ H ^{+}\right]=\left[ OH ^{-}\right]= mol \,L^{-1}$
$\therefore K _{ w }=\left( mol\, L ^{-1}\right)^2= mol ^2\, L ^{-2}$
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
$N_2H_5 ^+ + NH_3$ $\rightleftharpoons $ $NH_4^+ + N_2H_4$
$NH_3 + HBr $ $\rightleftharpoons $ $NH_4^+ + Br^-$
$N_2H_4 + HBr$ $\rightleftharpoons $ $N_2H_5^+ + Br^-$
Based on this information, what is the order of acidic strength -