MCQ
The unit of molar conductivity is
- A${\Omega ^{ - 1}}c{m^{ - 2}}mo{l^{ - 1}}$
- B${\Omega ^{}}c{m^{ - 2}}mo{l^{ - 1}}$
- ✓${\Omega ^{ - 1}}c{m^2}mo{l^{ - 1}}$
- D$\Omega \;c{m^2}mol$
So its unit will be ${\Omega ^{ - 1}}c{m^2}mo{l^{ - 1}} $ .
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$(A)$ Over all order of this reaction is one
$(B)$ Order of this reaction can't be determined
$(C)$ In region$-I$ and $III$, the reaction is of first and zero order respectively
$(D)$ In region$-II$, the reaction is of first order
$(E)$ In region$-II$, the order of reaction is in the range of $0.1$ to $0.9$.

| Rate constant | Activation energy | |
| Step $1$ | $k_1$ | $E_{a1} = 180\ kJ/mol$ |
| Step $2$ | $k_2$ | $E_{a2} = 80\ kJ/mol$ |
| Step $3$ | $k_3$ | $E_{a3} = 50\ kJ/mol$ |
If overall rate constant, $k = {\left( {\frac{{{k_1}{k_2}}}{{{k_3}}}} \right)^{2/3}}$ ,then overall activation energy of the reaction will be .......... $ kJ/mol$