MCQ
The $UPAC$ name of the compound $C{H_2} = CH - C{H_2} - C{H_2} - C \equiv CH$ is
- A$1, 5-$hexenyne
- B$1-$hexyne$-5-$ene
- C$1, 5-$hexynene
- ✓$1-$hexene$-5-$yne
So, the IUPAC name of the given formula is hex-$1$-en-$5$-yne or $1$-hexene-$5$-yne.
$\stackrel{1}{ CH _2}=\stackrel{2}{ CH }-\stackrel{3}{ CH _2}-\stackrel{4}{ C } H _2-\stackrel{5}{ C } \equiv \stackrel{6}{ CH }$
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$C{O_2} + 2{H_2}O\, \rightleftharpoons {H_3}{O^ + } + HCO_3^ - $
for which the equilibrium constant is $3.8 \times 10^{-7}$ and $pH = 6.0$. The ratio of $[HCO_3^- ]$ to $[CO_2]$ would be :-