MCQ
The value of $\frac{4\sqrt{12}}{12\sqrt{27}}$ is:
  • A
    $\frac{4}{9}$
  • B
    $\frac{8}{9}$
  • $\frac{2}{9}$
  • D
    $\frac{1}{9}$

Answer

Correct option: C.
$\frac{2}{9}$
$\frac{4\sqrt{12}}{12\sqrt{27}}$
$=\frac{4\sqrt{4\times3}}{12\sqrt{9\times3}}$
$=\frac{8\sqrt{3}}{36\sqrt{3}}$
$=\sqrt{\frac{(\sqrt{2}-1)^2}{2-1}}$
$=\sqrt{(\sqrt{2}-1)^2}$
$=1.414-1$
$=0.414$
$=\frac{2}{9}$

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