The value of H - E for the following reaction at 27 ,^o C will be… - Vidyadip

MCQ

The value of $\Delta H - \Delta E$ for the following reaction at ${27\,^o}C$ will be $2N{H_3}(g)\, \to \,{N_2}(g) + 3{H_2}(g)$

A
$8.314 \times 273 \times ( - 2)$
B
$8.314 \times 300 \times ( - 2)$
C
$8.314 \times 27 \times ( - 2)$
✓
$8.314 \times 300 \times (2)$

✓

Answer

Correct option: D.

$8.314 \times 300 \times (2)$

(d)$\Delta H - \Delta E = \Delta nRT$
also, $2N{H_{3(g)}} \to {N_{2(g)}} + 3{H_{2(g)}}$
$\Delta n = 2$.

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