MCQ
The value of $\lambda $ for which points $A(2,2,1)$ , $B(1,1,1)$ , $C(-\lambda ,2,1)$ and $D(3,0,-1)$ are coplanar, is $\lambda =$ ............
- ✓$-2$
- B$1$
- C$2$
- D$-1$
$\Rightarrow\left|\begin{array}{ccc}{-1} & {-1} & {0} \\ {-\lambda-2} & {0} & {0} \\ {1} & {-2} & {-2}\end{array}\right|=0 \Rightarrow \lambda=-2$
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
| List-$I$ | List-$II$ |
| ($I$) Probability of $\left(X_2 \geq Y_2\right)$ is | ($P$) $\frac{3}{8}$ |
| ($II$) Probability of $\left(X_2>Y_2\right)$ is | ($Q$) $\frac{11}{16}$ |
| ($III$) Probability of $\left(X_3=Y_3\right)$ is | ($R$) $\frac{5}{16}$ |
| ($IV$) Probability of $\left(X_3>Y_3\right)$ is | ($S$) $\frac{355}{864}$ |
| ($T$) $\frac{77}{432}$ |
The correct option is:
$\log2-1$
$\log2$
$\log4-1$
$-\log2$