MCQ
The value of $\left| {\,\begin{array}{*{20}{c}}a&{a + b}&{a + 2b}\\{a + 2b}&a&{a + b}\\{a + b}&{a + 2b}&a\end{array}\,} \right|$ is equal to
- A$9{a^2}(a + b)$
- ✓$9{b^2}(a + b)$
- C${a^2}(a + b)$
- D${b^2}(a + b)$
= $3\,(a + b)\,\left| {\,\begin{array}{*{20}{c}}1&{a + b}&{a + 2b}\\1&a&{a + b}\\1&{a + 2b}&a\end{array}\,} \right|$
Operate ${R_3} \to {R_3} - {R_1}$, ${R_2} \to {R_2} - {R_1}$
= $3\,(a + b)\,\left| {\,\begin{array}{*{20}{c}}1&{a + b}&{a + 2b}\\0&{ - b}&{ - b}\\0&b&{ - 2b}\end{array}\,} \right|$
$ = 3(a + b)\,(2{b^2} + {b^2}) = 9{b^2}(a + b)$.
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$P:\left|z_2-z_1\right|+\left|z_3-z_2\right|+\ldots+\left|z_{10}-z_9\right|+\left|z_1-z_{10}\right| \leq 2 \pi$
$Q:\left|z_2^2-z_1^2\right|+\left|z_3^2-z_2^2\right|+\ldots .+\left|z_{10}^2-z_9^2\right|+\left|z_1^2-z_{10}^2\right| \leq 4 \pi$
Then,