MCQ
The value of $\mathop {\lim }\limits_{x \to 2} \frac{{{3^{x/2}} - 3}}{{{3^x} - 9}}$ is
- A$0$
- B$1/3$
- ✓$1/6$
- D$\ln 3$
$ = \mathop {{\rm{lim}}}\limits_{x \to 2} \,\frac{1}{{{3^{x/2}} + 3}} = \frac{1}{6}$.
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