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Trigonometry – II — Maths STD 11 Science — Question

Maharashtra BoardEnglish MediumSTD 11 ScienceMathsTrigonometry – II2 Marks
MCQ
The value of sin $105^{\circ}$ is
  • ✓
    $\frac{\sqrt{3}+1}{2 \sqrt{2}}$
  • B
    $\frac{\sqrt{3}-1}{2 \sqrt{2}}$
  • C
    $-\frac{\sqrt{3}+1}{2 \sqrt{2}}$
  • D
    $\frac{1-\sqrt{3}}{2 \sqrt{2}}$
✓

Answer

Correct option: A.
$\frac{\sqrt{3}+1}{2 \sqrt{2}}$
(A)
$\sin 105^{\circ}=\sin \left(60^{\circ}+45^{\circ}\right)$
$=\sin 60^{\circ} \cos 45^{\circ}+\cos 60^{\circ} \sin 45^{\circ}$
$=\frac{\sqrt{3}+1}{2 \sqrt{2}}$

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