MCQ
The value of $\sqrt{3-2 \sqrt{2}}$ is
- A$\sqrt{2}+\sqrt{1}$
- ✓$\sqrt{2}-\sqrt{1}$
- C$\sqrt{3}+\sqrt{2}$
- D$\sqrt{3}-\sqrt{2}$
✓
Answer
Correct option: B.
$\sqrt{2}-\sqrt{1}$
$=\sqrt{3-2 \sqrt{2}}$
$=\sqrt{(\sqrt{2})^2+(1)^2-2 \times \sqrt{2} \times 1}$
$=\sqrt{(\sqrt{2}-1)^2}$
$=(\sqrt{2}-1)$
$=\sqrt{(\sqrt{2})^2+(1)^2-2 \times \sqrt{2} \times 1}$
$=\sqrt{(\sqrt{2}-1)^2}$
$=(\sqrt{2}-1)$
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