MCQ
The value of $\sqrt{3-2\sqrt2},$ is:
- ✓$\sqrt2-1$
- B$\sqrt2+1$
- C$\sqrt3-\sqrt2$
- D$\sqrt3+\sqrt2$
✓
Answer
Correct option: A.
$\sqrt2-1$
$\sqrt{3-2\sqrt2}$
$=\sqrt{2+1-2\sqrt2}$
$=\sqrt{\big(\sqrt2\big)^2+(1)^2-2\big(\sqrt2\big)(1)}$
$=\sqrt{\big(\sqrt2-1\big)^2}$
$=\sqrt2-1$
Hence, correct option is $(a).$
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