MCQ
The value of x for which $|\text{x} + 1|+\sqrt{(\text{x} – 1)} = 0$
  • A
    0
  • B
    1
  • C
    -1
  • D
    No value of x

Answer

  1. No value of x

Solution:

Given, $|\text{x} + 1| +\sqrt{(\text{x} – 1)}= 0, $where each term is non - negative.

So, $ |\text{x} + 1| = 0 $ and $\sqrt{\text{(x-1})}=0$ should be zero simultaneously.

$\text{i}.\text{e}. \text{x} = -1 $ and $\text{x}=1,$ which is not possible.

So, there is no value of x for which each term is zero simultaneously.

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Similar questions

If the circles x2 + y2 + 2ax + c = 0 and x2 + y2 + 2by + c = 0 touch each other, then:
  1. $\frac{1}{\text{a}^2}+\frac{1}{\text{b}^2}=\frac{1}{\text{c}}$
  2. $\frac{1}{\text{a}^2}+\frac{1}{\text{b}^2}=\frac{1}{\text{c}}$
  3. $\text{a}+\text{b}=2\text{c}$
  4. $\frac{1}{\text{a}}+\frac{1}{\text{b}}=\frac{2}{\text{c}}$

If the points A (1, 2), B (2, 4) and C (3, a) are collinear, what is the length BC?

Equation of vertical line to the right of y-axis at 5 units from y-axis is:

Suppose A1, A2, ..., A30  are thirty sets each having 5 elements and B1, B2, ..., Bn are n sets each with 3 elements. Let $\bigcup\limits^{30}_\text{i = 1}\text{A}_\text{i}=\bigcup\limits^{\text{n}}_\text{j = 1}\text{B}_\text{j}=\text{S}$  and each element of S belong to exactly 10 of the Ai's and exactly 9 of the Bj's, then n is equal to:
  1. 15
  2. 3
  3. 45
  4. 35.
Determine the nature of roots of the equation $\text{x}^2+2\text{x}\sqrt{3}+3=0.$
If R is a relation from a finite set A having m elements of a finite set B having n elements, then the number of relations from A to B is:
Choose the correct answer.
Let a, b, c, d, e be the observations with mean m and standard deviation s. The standard deviation of the observations a + k, b + k, c + k, d + k, e + k is:
If sum of all the coefficients in the expansion of $\Big(\text{x}^{\frac{3}{2}}+\text{x}^{\frac{1}{3}}\Big)^{\text{n}}$ is 128, then the coefficient of x5 is:
    Let $f(x)=x^3$. Then, dom (f) and range ( $f$ ) are respectively
    Number of odd numbers of five distinct digits can be formed by the digits 0, 1, 2, 3, 4, is: