MCQ
The velocity of train increases uniformly from $20\; km / h$ to $60\; km / h$ in $4\; hours$. The distance travelled by the train during this period is
- ✓$160$
- B$180$
- C$100$
- D$120$
$60=20+(a \times 4)$
$a=\frac{60-20}{4}=10 \;km / h ^{2}$.
$d=u t+\frac{1}{2} a t^{2}=(20 \times 4)+\frac{1}{2} \times 10 \times(4)^{2}=160 \;km$
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