The vertex of the parabola =y^2-4 y-x+3=0 is: - Vidyadip

MCQ

The vertex of the parabola $=y^2-4 y-x+3=0$ is:

A
(-1, 3)
✓
(-1, 2)
C
(2, -1)
D
(3, -1)

✓

Answer

Correct option: B.

(-1, 2)

(-1, 2)

Solution:
We have,
$=y^2-4 y-x+3=0$
$\Rightarrow(y-2)^2-4-x+3=0$
$\Rightarrow(y-2)^2=(x+1)$
$\therefore$ Vertex of the parabola $=(-1,2)$

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