Question
The voltage and current in a series AC circuit are given by, $\text{V}=\text{V}_0\cos\omega\text{t}$ and $\text{i}=\text{i}_0\sin\omega\text{t}.$ What is the power dissipated in the circuit?

Answer

Power $=\text{I}_\text{rms}\text{E}_\text{rms}\cos\phi$$\phi=\frac{\pi}{2}$ so $\text{P}=0.$

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