MCQ
The volume, in $mL ,$ of $0.02\, M K _{2} Cr _{2} O _{7}$ solution required to react with $0.288\, g$ of ferrous oxalate in acidic medium is........
(Molar mass of $Fe =56\, g\, mol ^{-1}$ )
- A$55$
- B$52$
- C$60$
- ✓$50$
(Molar mass of $Fe =56\, g\, mol ^{-1}$ )
$n=6 \quad \quad n=3$
$\frac{0.02 \times 6 \times V ( mL )}{1000}=\frac{0.288}{144} \times 3$
$\Rightarrow \quad V =50 mL$
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