MCQ
The wave length of light in visible part $({\lambda _V})$ and for sound $({\lambda _S})$ are related as
- A${\lambda _V} > {\lambda _S}$
- ✓${\lambda _S} > {\lambda _V}$
- C${\lambda _S} = {\lambda _V}$
- DNone of these
✓
Answer
Correct option: B.
${\lambda _S} > {\lambda _V}$
b
We know that the speed of the sound is comparatively very small as compared to the speed of the light. So, the wavelength of the sound wave will be very large as compared to the wavelength of the visible part.
We know that the speed of the sound is comparatively very small as compared to the speed of the light. So, the wavelength of the sound wave will be very large as compared to the wavelength of the visible part.
$\therefore \lambda_S > \lambda_N$
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