MCQ
The wavelength of light observed on the earth, from a moving star is found to decrease by $0.05 \%$. Relative to the earth the star is
  • A
    Moving away with a velocity of $1.5 \times 10^5 m / s$
  • Coming closer with a velocity of $1.5 \times 10^5 m / s$
  • C
    Moving away with a velocity of $1.5 \times 10^4 m / s$
  • D
    Coming closer with a velocity of $1.5 \times 10^4 m / s$

Answer

Correct option: B.
Coming closer with a velocity of $1.5 \times 10^5 m / s$
$\frac{\Delta \lambda}{\lambda}=\frac{v}{c} \Rightarrow \frac{0.05}{100}=\frac{v}{3 \times 10^8} \Rightarrow v=1.5 \times 10 m / s$(Since wavelength is decreasing, so star coming closer)

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