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A body of capacity $4\,\mu \,F$ is charged to $80\,V$ and another body of capacity $6\,\mu \,F$ is charged to $30\,V$. When they are connected the energy lost by $4\,\mu \,F$ capacitor is.......$mJ$
The distance between plates of a parallel plate capacitor is $5d$. Let the positively charged plate is at $ x=0$ and negatively charged plate is at $x=5d$. Two slabs one of conductor and other of a dielectric of equal thickness $d$ are inserted between the plates as shown in figure. Potential versus distance graph will look like :
A charge $3$ coulomb experiences a force $3000$ $N$ when placed in a uniform electric field. The potential difference between two points separated by a distance of $1$ $cm$ along the field lines is.....$V$
At a distance $l$ from a uniformly charged long wire, a charged particle is thrown radially outward with a velocity $u$ in the direction perpendicular to the wire. When the particle reaches a distance $2 l$ from the wire, its speed is found to be $\sqrt{2} u$. The magnitude of the velocity, when it is a distance $4 l$ away from the wire is (ignore gravity)
Two charges $ + 3.2 \times {10^{ - 19}}\,C$ and $ - 3.2 \times {10^{ - 19}}\,C$ kept $2.4\, \mathop A\limits^o $ apart forms a dipole. If it is kept in uniform electric field of intensity $4 \times {10^5}\,volt/m$ then what will be its electrical energy in equilibrium
A capacitor of capacity $C$ is charged to a steady potential difference $V$ and connected in series with an open key and a pure resistor $'R'$. At time $t = 0$, the key is closed. If $I =$ current at time $t$, a plot of log $I$ against $'t'$ is as shown in $(1)$ in the graph. Later one of the parameters i.e. $V, R$ or $C$ is changed keeping the other two constant, and the graph $(2)$ is recorded. Then
An air filled parallel plate capacitor has capacity $C$. If distance between plates is doubled and it is immersed in a liquid then capacity becomes twice. Dielectric constant of the liquid is