The wavelengths of two waves are $50$ and $51 cm$ respectively. If the temperature of the room is  ${20^o}C$, then what will be the number of beats produced per second by these waves, when the speed of sound at  ${0^o}C$ is $\,332 m/sec$
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(a) ${v_0} = 332\, m/s$. Velocity sound at $t°C$ is ${v_t} = ({v_0} + 0.61\,t)$
==> ${v_{20}} = {v_0} + 0.61 \times 20 = 344.2$$m/s$
==> $\Delta n = {v_{20}}\left( {\frac{1}{{{\lambda _1}}} - \frac{1}{{{\lambda _2}}}} \right)$$ = 344.2\left( {\frac{{100}}{{50}} - \frac{{100}}{{51}}} \right) = 14$
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