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11. thermodynamics — Physics STD 11 Science — Question

Gujarat BoardEnglish MediumSTD 11 SciencePhysics11. thermodynamics1 Mark
MCQ
The work of $146\,kJ$ is performed in order to compress one kilo mole of a gas adiabatically and in this process the temperature of the gas increases by $7\,^oC$ . The gas is $(R = 8.3\, J\, mol^{-1}\, K^{-1})$
  • ✓
    diatomic
  • B
    triatomic
  • C
    a mixture of monoatomic and diatomic
  • D
    monoatomic
✓

Answer

Correct option: A.
diatomic
a
$w=\frac{n R \Delta T}{\gamma-1}$

$146 \times 10^{3}=\frac{10^{3} \times 8.3 \times 7}{\gamma-1}$

$\gamma-1=\frac{8.3 \times 7}{146}=\frac{58.1}{146}$

$\gamma=\frac{58}{146}+1$

$\gamma=\frac{58+146}{146}$

$=\frac{204}{146}$

$=\frac{7}{5}$ diatomic nature.

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