MCQ
The Zero of the polynomial $(x-2)^2-(x+2)^2$ is:
- A$1$
- B$-2$
- ✓$0$
- D$2$
✓
Answer
Correct option: C.
$0$
$(x-2)^2-(x+2)^2$
$= (x - 2 + x + 2) (x - 2 - x - 2) [$Using identity $a^2-b^2 = (a + b) (a - b)]$
$= (2x) (-4)$
$= -8x$
Then the zero is,
$-8 = 0$
$⇒ x = 0$
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