MCQ
The zero of the polynomial $(x-2)^2-(x+2)^2$ is:
- ✓$0$
- B$2$
- C$1$
- D$-2$
✓
Answer
Correct option: A.
$0$
$(x-2)^2-(x+2)^2$$=(x-2+x+2)(x-2-x-2)[\text { Using identity] }$
$a^2-b^2=(a+b)(a-b)$
$=(2 x)(-4)$
$=-8 x$
Then the zero is,
$-8 x=0$
$\Rightarrow x=0$
$a^2-b^2=(a+b)(a-b)$
$=(2 x)(-4)$
$=-8 x$
Then the zero is,
$-8 x=0$
$\Rightarrow x=0$
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