MCQ
$x = 2, y = -1$ is a solution of the linear equation:
- ✓$x + 2y = 0$
- B$x + 2y = 4$
- C$2x + y = 0$
- D$2x + y = 5$
✓
Answer
Correct option: A.
$x + 2y = 0$
Substituting $x = 2$ and $y = -1$ in the following equations:
$L.H.S. = x + 2y = 2 + 2(-1) = 2 - 2 = 0 = R.H.S.$
$L.H.S. = x + 2y = 2 + 2(-1) = 2 - 2 = 0 ≠ 4 ≠ R.H.S.$
$L.H.S. = 2x + y = 2(2) + (-1) = 4 - 1 = 3 ≠ 0 ≠ R.H.S.$
$L.H.S. = 2x + y = 2(2) + (-1) = 4 - 1 = 3 ≠ 5 ≠ R.H.S.$
Hence, correct option is $(a).$
$L.H.S. = x + 2y = 2 + 2(-1) = 2 - 2 = 0 = R.H.S.$
$L.H.S. = x + 2y = 2 + 2(-1) = 2 - 2 = 0 ≠ 4 ≠ R.H.S.$
$L.H.S. = 2x + y = 2(2) + (-1) = 4 - 1 = 3 ≠ 0 ≠ R.H.S.$
$L.H.S. = 2x + y = 2(2) + (-1) = 4 - 1 = 3 ≠ 5 ≠ R.H.S.$
Hence, correct option is $(a).$
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