There are 25 tickets numbered as 1, 2, 3, 4, ..., 25 respectively… - Vidyadip

MCQ

There are $25$ tickets numbered as $\{1, 2, 3, 4, ..., 25\}$ respectively. One ticket is drawn at random. what is the probability that the number on the ticket is a multiple of $3$ or $5?$

A
$\frac{2}{5}$
B
$\frac{11}{25}$
✓
$\frac{12}{25}$
D
$\frac{13}{25}$

✓

Answer

Correct option: C.

$\frac{12}{25}$

The total number of tickets $= 25$
The multiples of $3$ are $\{3, 6, 9, 12, 15, 18, 21, 24.\}$
The multiples of $5$ are $5, 10, 15, 20$ and $25.$
Since $15$ is a multiple of $3$ as $5,$ it is to be caculated only once.
So, there are $12$ numbers
$P($getting a multiple of $3$ or $5)$
$=\frac{12}{25}$

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