There are two identical capacitors, the first one is uncharged and filled with a dielectric of constant $K$ while the other one is charged to potential $V$ having air between its plates. If two capacitors are joined end to end, the common potential will be
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(d)
$V^{\prime}=\frac{K C(0)+C V}{K C+C}$
$V^{\prime}=\frac{C V}{C(1+K)}$
$V^{\prime}=\frac{V}{1+K}$
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