There are two wires of same material and same length while the diameter of second wire is $2$ times the diameter of first wire, then ratio of extension produced in the wires by applying same load will be
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(d) $l = \frac{{FL}}{{AY}}$ $\Rightarrow$ $l \propto \frac{1}{{{r^2}}}$ $(F, L$ and $Y$ are constant$)$
$\frac{{{l_1}}}{{{l_2}}} = {\left( {\frac{{{r_2}}}{{{r_1}}}} \right)^2} = {(2)^2} = 4$
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