MCQ
There are two wires of same material and same length while the diameter of second wire is 2 times the diameter of first wire, then ratio of extension produced in the wires by applying same load will be
  • A
    $1: 1$
  • B
    $2: 1$
  • C
    $1: 2$
  • $4: 1$

Answer

Correct option: D.
$4: 1$
(d)
$l=\frac{F L}{A Y}$
$ \therefore l \propto \frac{1}{r^2}(F, L \text { and } Y \text { are constant })$
$ \frac{l_1}{l_2}=\left(\frac{r_2}{r_1}\right)^2=(2)^2=4$

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