where $F=$ force is required to move the plate
$\tau=$ Shear stress
$A=$ Area of plate
$\mu=$ coeffecient of viscosity of glycerine
$y=g a p$
$\mathrm{u}=$ velocity
$\frac{F}{10^{-2}}=1 \times \frac{0.07}{0.001}$
Thus $F=0.7 \mathrm{N}$
$(A)$ $\beta=0$ when $a= g / \sqrt{2}$
$(B)$ $\beta>0$ when $a= g / \sqrt{2}$
$(C)$ $\beta=\frac{\sqrt{2}-1}{\sqrt{2}}$ when $a= g / 2$
$(D)$ $\beta=\frac{1}{\sqrt{2}}$ when $a= g / 2$
