There is a simple pendulum hanging from the ceiling of a lift. When the lift is stand still, the time period of the pendulum is $T$. If the resultant acceleration becomes $g/4,$ then the new time period of the pendulum is
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(c) $T \propto \frac{1}{{\sqrt g }}$
==> $\frac{{{T_2}}}{{{T_1}}} = \sqrt {\frac{{{g_1}}}{{{g_2}}}} $
$ = \sqrt {\left( {\frac{g}{{g/4}}} \right)} $
==> ${T_2} = 2{T_1} = 2T$
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