MCQ
This conversion can be achieved by
- A$Me_2CO/H^+ , H_3O^{\oplus} , KMnO_4/HO^-$
- ✓$Me_2CO/H^+ , KMnO_4 , H_3O^+$
- C$KMnO_4 /NaO_4 , Me_2CO/H^+ , H_3O^+$
- D$KMnO_4 /NaIO_4 , H_3O^+ , Me_2CO/H^+$
✓
Answer
Correct option: B.
$Me_2CO/H^+ , KMnO_4 , H_3O^+$
b
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