Three capacitors are connected as shown in fig. Then the charge on capacitor $C_1$ is.....$\mu C$
A$6$
B$12$
C$18$
D$24$
Medium
Download our app for free and get started
A$6$
a Potential at $\mathrm{A}=\frac{\mathrm{C}_{1} \mathrm{V}_{1}+\mathrm{C}_{2} \mathrm{V}_{2}+\mathrm{C}_{3} \mathrm{V}_{3}}{\mathrm{C}_{1}+\mathrm{C}_{2}+\mathrm{C}_{3}}$
$=3$ $volt$
$\therefore$ Charge of $C_{1}=Q_{1}=C_{1}(6-3)$
$=2\, \mu \mathrm{F} \times 3=6\, \mu \mathrm{C}$
Download our app
and get started for free
Experience the future of education. Simply download our apps or reach out to us for more information. Let's shape the future of learning together!No signup needed.*
In a parallel plate capacitor the separation between the plates is $3\,mm$ with air between them. Now a $1\,mm$ thick layer of a material of dielectric constant $2$ is introduced between the plates due to which the capacity increases. In order to bring its capacity to the original value the separation between the plates must be made......$mm$
An electric dipole with dipole moment $\vec p = (3i + 4j) \times 10^{-30} C-m$ is placed in an electric field $\vec E = 4000 \hat i (N/C).$ An external agent turns the dipole slowly until its electric dipole moment becomes $(-4 \hat i + 3 \hat j) ×10^{-30}C-m.$ The work done by the external agent is equal to :-
A small sphere carrying a charge ‘$q$’ is hanging in between two parallel plates by a string of length $L$. Time period of pendulum is ${T_0}$. When parallel plates are charged, the time period changes to $T$. The ratio $T/{T_0}$ is equal to
Two large circular discs separated by a distance of $0.01 m$ are connected to a battery via a switch as shown in the figure. Charged oil drops of density $900 kg m ^{-3}$ are released through a tiny hole at the center of the top disc. Once some oil drops achieve terminal velocity, the switch is closed to apply a voltage of $200 V$ across the discs. As a result, an oil drop of radius $8 \times 10^{-7} m$ stops moving vertically and floats between the discs. The number of electrons present in this oil drop is (neglect the buoyancy force, take acceleration due to gravity $=10 ms ^{-2}$ and charge on an electron ($e$) $=1.6 \times 10^{-19} C$ )
A parallel plate capacitor has potential $20\,kV$ and capacitance $2\times10^{-4}\,\mu F$. If area of plate is $0.01\,m^2$ and distance between the plates is $2\,mm$ then find dielectric constant of medium