Maharashtra BoardEnglish MediumSTD 12 SciencePhysicsElectrostatics3 Marks
Question
Three capacitors are connected as shown in the figure below. Calculate the effective capacitance between $A$ and $B.$
✓
Answer
Data: $C _1=2 \mu F , C _2=3 \mu F , C _3=4 \mu F$
The resultant capacitance $C_5$ of $C_1$ and $C_2$ in series is given by
$\frac{1}{C_n}=\frac{1}{C_1}+\frac{1}{C_2}=\frac{1}{2}+\frac{1}{3}=\frac{5}{6}$
$\therefore C_5=\frac{6}{5}=1.2 \mu F$
The effective capacitance between $A$ and $B$ is due to the parallel combination of $C_5$ and $C_3$.
$C_p=C_5+C_3=1.2+4=5.2 \mu F$
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