Question
Three coins are tossed together. Write all the possible outcomes. Now, find the probability of getting: at least two heads

Answer

When three coins are tossed, possible outcomes are:
HHH,HHT,HTH,HTT,THH,THT,TTH,TTT
Total possible outcomes $=8$
Faavvorable outcomes for at least two heads= $HHT , THH , HTH , HHH$
Number of favorable outcomes $=4$
$P ($ at least two heads $)=\frac{4}{8}=\frac{1}{2}$

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