MCQ
Three identical dice are rolled. The probability that same number will appear on each of them will be
- A$\frac{1}{6}$
- ✓$\frac{1}{{36}}$
- C$\frac{1}{{18}}$
- D$\frac{3}{{28}}$
Hence required probability $ = \frac{6}{{216}} = \frac{1}{{36}}.$
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