MCQ
Three identical dice are rolled. What is the probability that the same number will appear on each of them?
- A$\frac{1}{6}$
- B$\frac{1}{36}$
- C$\frac{1}{18}$
- D$\frac{3}{28}$
✓
Answer
- $\frac{1}{36}$
Solution:
Total number of cases = 6³ = 216
The same number can appear on each of the dice in the following ways:
(1, 1, 1), (2, 2, 2), ………….(3, 3, 3)
So, favourable number of cases = 6
Hence, required probability = 6/216 = 1/3
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