MCQ
Three inductances are connected as shown below. Assuming no coupling, the resultant inductance will be.....$H$
- A$0.25$
- B$0.75$
- C$0.01$
- ✓$1$
✓
Answer
Correct option: D.
$1$
d
$L_{2}$ and $L_{3}$ are in parallel. Thus their combination
$L_{2}$ and $L_{3}$ are in parallel. Thus their combination
gives $L^{\prime}=\frac{L_{2} L_{3}}{L_{2}+L_{3}}=0.25 \mathrm{\,H}$
The $L^{\prime}$ and $L_{1}$ are in series, thus the equivalent inductance is $L=L_{1}+L^{\prime}=0.75+0.25=1 \,H$
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