Three processes form a thermodynamic cycle as shown on P-V diagram for an ideal gas. Process 1 rightarrow 2 takes place at constant temperature (300K).

Q: Three processes form a thermodynamic cycle as shown on $P-V$ diagram for an ideal gas. Process $1 \rightarrow 2$ takes place at constant temperature $(300K$). Process $2 \rightarrow 3$ takes place at constant volume. During this process $40J$ of heat leaves the system. Process $3 \rightarrow 1$ is adiabatic and temperature $T_3$ is $275K$. Work done by the gas during the process $3 \rightarrow 1$ is ..... $J$

a In the process $1 \rightarrow 2, \Delta Q_{1 \rightarrow 2}=\Delta W_{1 \rightarrow 2}$ In the process $2 \rightarrow 3, \Delta W_{2 \rightarrow 3}=0$ In the process $3 \rightarrow 1, \Delta Q_{3 \rightarrow 1}=0$ The complete process being cyclic, $\Delta U=0$ Hence $\Delta Q=\Delta W \Rightarrow \Delta Q_{1 \rightarrow 2}+\Delta Q_{2 \rightarrow 3}+\Delta Q_{3 \rightarrow 1}=\Delta W_{1 \rightarrow 2}+\Delta W_{2 \rightarrow 3}+\Delta W_{3 \rightarrow 1} \Rightarrow$ $\Delta Q_{2 \rightarrow 3}=\Delta W_{3 \rightarrow 1}=-40 J$

SECTION - A [PHYSICS - MCQ]

GSEB - English Medium

Three processes form a thermodynamic cycle as shown on $P-V$ diagram for an ideal gas. Process $1 \rightarrow 2$ takes place at constant temperature $(300K$). Process $2 \rightarrow 3$ takes place at constant volume. During this process $40J$ of heat leaves the system. Process $3 \rightarrow 1$ is adiabatic and temperature $T_3$ is $275K$. Work done by the gas during the process $3 \rightarrow 1$ is ..... $J$

A$-40$
B$-20$
C$+40$
D$+20$

Advanced

STD 11 Science
NEET
STD 11 - 11. thermodynamics
Physics

Download our app
and get started for free

Experience the future of education. Simply download our apps or reach out to us for more information. Let's shape the future of learning together!No signup needed.*

Download App

Download our appand get started for free

Similar Questions

Download our app
and get started for free