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Model Paper 3 — Maths STD 9 — Question

Gujarat BoardEnglish MediumSTD 9MathsModel Paper 31 Mark
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Answer

(c) 2
Explanation: Adjusted frequency $=\left(\frac{\text { frequency of the class }}{\text { width of the class }}\right) \times 5$
Therefore, Adjusted frequency of $25-45=\frac{8}{20} \times 5=2$

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