Total number of d electrons present an element with atomic no. 78… - Vidyadip

Question

Total number of $d$ electrons present an element with atomic no. $78$ is

✓

Answer

d
${}_{78}Pt = 3{d^{10}} + 4{d^{10}} + 5{d^9} = 29\,{e^{ - 1}}s$

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