- A$3$
- ✓$2$
- C$1$
- D$0$
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$ \text { a } \mathrm{Cl}_2(\mathrm{~g})+\mathrm{b} \mathrm{OH}^{-}(\mathrm{aq}) \rightarrow \mathrm{c} \mathrm{ClO}^{-}(\mathrm{aq})+\mathrm{d} \mathrm{Cl}^{-}(\mathrm{aq}) +\mathrm{e} \mathrm{H}_2 \mathrm{O}(l)$
The values of $a, \ b,\ c$ and $d$ in a balanced redox reaction are respectively :

Here $W, Y$ and $Z$ are left, up and right elements with respect to the element $'X'$ and $'X'$ belongs to $16^{th}$ group and $3^{rd}$ period. Then according to given information the incorrect statement regarding given elements is

$Si_2H_6(g)\,\,+\,\,H_2(g)\,\,\to \,\, 2SiH_4(g),\,\,\Delta H\,\,=\,\,-\,11.7\,\,kJ/mol$
$SiH_4(g)\,\,\to \,\,SiH_2(g)\,\,+\,\,H_2(g),\,\, \Delta H\,\,=\,\,+239.7\,\,kJ/mol$
$\Delta H_f^o\,\,Si_2H_6(g)\,\,=\,\,80.3\,\,kJ/mol$
......$kJ/mol$