The number of turns in primary coil is: \(N_{z}=10\)

The voltage across secondary coil: \(V_{z}=50 V\)

The voltage across the primary coil,

\(\frac{V_{p}}{V_{s}}=\frac{500}{10}\)

\(\frac{V_{p}}{50}=\frac{500}{10}\)

\(V_{p}=2500 V\)

The current across the secondary coil is,

\(i_{s}=\frac{V_{s}}{R}=\frac{50}{10}=5 A\)

The current across the primary coil is,

\(\frac{i_{p}}{i_{s}}=\frac{V_{s}}{V_{p}}\)

\(\frac{i_{p}}{5}=\frac{500}{2500}\)

\(i_{p}=1 A\)