Question
Truth table for the given circuit will be

Answer

Truth table of the circuit is as follows
$x$ $y$ $\bar x$ $a= x.y$ $b=\bar x.y$ $z=\bar {a.b}$
$0$ $0$ $1$ $0$ $0$ $1$
$0$ $1$ $1$ $0$ $1$ $1$
$1$ $0$ $0$ $0$ $0$ $1$
$1$ $1$ $0$ $1$ $0$ $1$

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