Two blocks, $4\, kg$ and $2\, kg$ are sliding down an inclined plane as shown in figure. The acceleration of $2\, kg$ block is ........ $m/s^2$ 
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$\therefore$ Net force $=\left(\mathrm{m}_{1}+\mathrm{m}_{2}\right)$ a $_{\mathrm{net}}$

$\therefore \quad\left(\mathrm{m}_{1}+\mathrm{m}_{2}\right) \mathrm{g} \sin \theta-\left(\mu \mathrm{m}_{1} \mathrm{g} \cos \theta+\mu \mathrm{m}_{2} \underline{\mathrm{g}} \cos \theta\right)$

$=\left(\mathrm{m}_{1}+\mathrm{m}_{2}\right) \mathrm{a}_{\mathrm{net}}$

$\therefore a_{n e t}=g\left(\sin \theta-\frac{\left(\mu m_{1}+\mu m_{2}\right) \cos \theta}{m_{1}+m_{2}}\right)$

Here, $m_{1}=4 \mathrm{kg}, \mathrm{m}_{2}=2 \mathrm{kg}, \theta=30^{\circ} ; \mu=0.3$

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