MCQ
Two blocks of masses $10 \; kg$ and $30 \; kg$ are placed on the same straight line with coordinates $(0,0) \; cm$ and $( x , 0) \; cm$ respectively. The block of $10 \; kg$ is moved on the same line through a distance of $6 \; cm$ towards the other block. The distance through which the block of $30 \; kg$ must be moved to keep the position of centre of mass of the system unchanged is
  • A
    $4 \; cm$ towards the $10 \; kg$ block
  • B
    $2 \; cm$ away from the $10 \; kg$ block
  • $2 \; cm$ towards the $10 \; kg$ block
  • D
    $4 \; cm$ away from the $10 \; kg$ block

Answer

Correct option: C.
$2 \; cm$ towards the $10 \; kg$ block
c
$\Delta x_{G}=\frac{m_{1} \Delta x_{1}+m_{2} \Delta x_{2}}{m_{1}+m_{2}}$

$0=\frac{10 \times 6+30\left(\Delta x_{2}\right)}{40}$

$\Delta x_{2}=-2 \; c m$

Block of mass $30 \; kg$ will to move towards $10 \; kg$.

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