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Motion in a Plane — Physics STD 11 Science — Question

Gujarat BoardEnglish MediumSTD 11 SciencePhysicsMotion in a Plane2 Marks
Question
Two bodies are thrown with same velocities at angles $\alpha$ and $(90^\circ-\alpha)$ with the horizontal. What will be the ratio of $(i)$ maximum heights attained by them $(ii)$ their horizontal ranges?
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Answer

  1. $\frac{\text{h}_1}{\text{h}_2}=\frac{\frac{\text{v}^2_0\sin^2\alpha}{2\text{g}}}{\frac{\text{v}^2_0\sin^2(90-\alpha)}{2\text{g}}}$
$=\frac{\sin^2\alpha}{\cos^2\alpha}=\tan^2\alpha$
  1. Horizontal ranges in both the cases are same, i.e.,
$\text{R}_1=\text{R}_2,\ \frac{\text{R}_1}{\text{R}_2}=1$

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