Question
Two capacitors each having capacitance $C$ and breakdown voltage $V$ are joined in series. The capacitance and the breakdown voltage of the combination will be:
✓
Answer
Since the voltage gets added up when the capacitors are connected in series, the voltage of the combination is $2V.$
Also, the capacitance of a series combination is given by
$\frac{1}{\text{C}_{\text{net}}}=\frac{1}{\text{C}_1}+\frac{1}{\text{C}_2}$
Here,
$C_{net} =$ Net capacitance of the combination
$\text{C}_1=\text{C}_2=\text{C}$
$\therefore\text{C}_{\text{net}}=\frac{\text{C}}{2}$
Also, the capacitance of a series combination is given by
$\frac{1}{\text{C}_{\text{net}}}=\frac{1}{\text{C}_1}+\frac{1}{\text{C}_2}$
Here,
$C_{net} =$ Net capacitance of the combination
$\text{C}_1=\text{C}_2=\text{C}$
$\therefore\text{C}_{\text{net}}=\frac{\text{C}}{2}$
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